Solve `ln ( x − 2) = 5` ?

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Solve `ln ( x − 2) = 5` ?

Postby Integr88 » Thu 14 April, 2011 16:27

solve for x in `ln ( x − 2) = 5`
we first write it as base `e`
`e^(ln(x-2))=e^5`
and we have:
`x-2=e^5` add 2 to both side `x-2+2=e^5+2` and we left with
`x=e^5+2`

solved.
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