how to evalueate `sin^(-1)(sqrt(3)/2)` ?

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how to evalueate `sin^(-1)(sqrt(3)/2)` ?

Postby admin » Mon 14 March, 2011 09:49

According to Thomas' Calculus early Transcendentals 12th Edition: Because `sin(pi/3)=sqrt(3/2)` and `pi/3` belong to the range [`-pi/2,pi/2`] fo the acrsine function.
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