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linear function of Starbucks locations

linear function of Starbucks locations

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linear function of Starbucks locations

Postby barnamah » Thu 07 April, 2011 20:13

Suppose that in 2003 there were approximately 6,400 Starbucks locations. Suppose
that in 2007 this number had grown to approximately 13, 168.
a. Write a linear function that represents the number of Starbucks n as a function of
time t. Let t = 0 represent 2003.
Explore and know. That is asked.
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Re: linear function of Starbucks locations

Postby Integr88 » Thu 07 April, 2011 20:25

we have find the function. Because it is liner, we have to represent it as y=mx+b
we have:
at 2003, 6400
at 2007, 13168
so `x_1=2003`, `y_1=6400`
and `x_2=2007`, `y_2=13168`


to get slope m we have to use:
`m=(y2-y1)/(x2-x1)` sub in the values `m=(13168-6400)/(2007-2003)=6768/4=1692`
so the slope m=1692

when know the initial data that we have at 2003 which is the begining, we can set x=0, y=6400 we had 6400. Using this information

y=mx+b
`6400=(1692)(0)+b`
`6400=b` so we found b=6400

our linear equation is y=1692t+6400
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