by Integr88 » Tue 29 March, 2011 16:30
I this is actually `ln(2(1+x/2))` and if we look at the inside ln we have `2(1+x/2)=2+x`
so we can rewrite the equation as ln(2+x). to differentiate it, it is `1/(2+x) * 1=1/(2+x)`
`:.` the final answer is `1/(2+x)`