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`y = x^(3/2) (1+x^2)^(1/2)`

`y = x^(3/2) (1+x^2)^(1/2)`

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Re: `y = x^(3/2) (1+x^2)^(1/2)`

Postby barnamah » Thu 14 April, 2011 06:53

so you are saying that for this equation `y = x^(3/2) (1+x^2)^(1/2)`
you see the answer is `1/2 x^(3/2) (1+x^2)^-(1/2) (5x^2 + 3)`

do we have to take the derivatives? or integrate it?
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